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If \(P\) is the product of all the positive multiples of 11

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by swerve » Sat Aug 03, 2019 10:46 am

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If \(P\) is the product of all the positive multiples of 11 less than 100, then what is the sum of the distinct primes of \(P\)?

A. 22
B. 28
C. 45
D. 49
E. 89

The OA is B

Source: Magoosh
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Source: — Problem Solving |

by Ian Stewart » Sun Aug 04, 2019 5:07 am
"the distinct primes of P" doesn't mean anything in math, if P is a number. I'm not sure if the question has been correctly transcribed, but they surely mean to say "the distinct prime divisors of P".

The product of the positive multiples of 11 less than 100 is:

(11)(22)(33) ... (99) = (1)(11)(2)(11)(3)(11) ... (9)(11) = 11^9 * 9!

and since 9! is divisible by the primes less than or equal to 9, so by 2, 3, 5, and 7, this product is divisible by the primes 2, 3, 5, 7 and 11, which sum to 28.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

ianstewartgmat.com
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by Scott@TargetTestPrep » Sun Aug 11, 2019 6:15 pm
swerve wrote:If \(P\) is the product of all the positive multiples of 11 less than 100, then what is the sum of the distinct primes of \(P\)?

A. 22
B. 28
C. 45
D. 49
E. 89

The OA is B

Source: Magoosh
We can create the following expression:

11 x 2(11) x 3(11) x 4(11) x 5(11) x 6(11) x 7(11) x 8(11) x 9(11)

We see that the prime factors of P are 2, 3, 5, 7, and 11. So, the sum of those distinct primes is 2 + 3 + 5 + 7 + 11 = 28.

Answer: B

Scott Woodbury-Stewart
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