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The area of square region S is what percent greater than the

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The area of square region S is what percent greater than the

by BTGmoderatorDC » Sun Aug 12, 2018 2:32 pm

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The area of square region S is what percent greater than the area of square region T?

1) The length of a side of square S is 10% greater than the length of a side of square T.
2) The length of a side of square S is 22 and the length of a side of square T is 20.

OA D

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by Jay@ManhattanReview » Mon Aug 13, 2018 12:22 am

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BTGmoderatorDC wrote:The area of square region S is what percent greater than the area of square region T?

1) The length of a side of square S is 10% greater than the length of a side of square T.
2) The length of a side of square S is 22 and the length of a side of square T is 20.

OA D

Source: GMAT Prep
Let's take each statement one by one.

1) The length of a side of square S is 10% greater than the length of a side of square T.

Say the length of the side of the square T is x unit; thus, the length of the side of the square S would be (x + 10% of x = 1.1x) unit

=> Area of the square T = x*x = x^2
=> Area of the square S = 1.1x*1.2x = 1.21x^2

Thus, the area of square region S is 21 percent greater than the area of square region T. Sufficient.

2) The length of a side of square S is 22 and the length of a side of square T is 20.

=> Area of the square T = 20*20 = 400
=> Area of the square S = 22*22 = 484

Thus, the area of square region S is [(484 - 400)/400)*100%] = 21 percent greater than the area of square region T. Sufficient.

The correct answer: D

Hope this helps!

-Jay
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