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The rear–most end of a 66 foot truck exits a 330 foot tunn

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The rear–most end of a 66 foot truck exits a 330 foot tunn

by AAPL » Thu May 31, 2018 5:03 am

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The rear-most end of a 66-foot truck exits a 330-foot tunnel exactly 6 seconds after the front-most ends of the truck entered the tunnel. If the truck traveled the entire tunnel at a uniform speed, what is the speed of the truck in miles per hour (1 mile = 5,280 feet)?

A. 225
B. 90
C. 45
D. 37.5
E. 27

The OA is C.

Is there a strategic approach to this PS question? Can anyone help, please? Thanks!
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by swerve » Thu May 31, 2018 10:13 am
total length will be 330+66=396
time=6 secs

speed=396/6=66feet/sec

conversion to miles per hour=66*3600/5280=45.

Answer C.

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by Jeff@TargetTestPrep » Fri Jun 01, 2018 11:56 am
AAPL wrote:The rear-most end of a 66-foot truck exits a 330-foot tunnel exactly 6 seconds after the front-most ends of the truck entered the tunnel. If the truck traveled the entire tunnel at a uniform speed, what is the speed of the truck in miles per hour (1 mile = 5,280 feet)?

A. 225
B. 90
C. 45
D. 37.5
E. 27
Let's find the distance traveled by the front-most end of the truck. After traveling the 330- foot tunnel, the front-most end travels an extra 66 feet before the rear-most end exits the tunnel. Thus, the truck travels 330 + 66 = 396 feet in 6 seconds.

Let's now convert 396 feet to miles and 6 seconds to hours.

396 feet = 396/5280 miles

6 seconds = 6/3600 = 1/600 hours.

Thus, the speed of the truck is (396/5280)/(1/600) = (396 x 600)/5280 = 45 miles per hour.

Answer: C

Jeffrey Miller
Head of GMAT Instruction
[email protected]

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