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An object thrown directly upward is at a height of \(h\) feet after \(t\) seconds, where \(h = -16 (t -3)^2 + 150.\) At

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An object thrown directly upward is at a height of \(h\) feet after \(t\) seconds, where \(h = -16 (t -3)^2 + 150.\) At

by M7MBA » Fri Oct 16, 2020 8:06 am

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An object thrown directly upward is at a height of \(h\) feet after \(t\) seconds, where \(h = -16 (t -3)^2 + 150.\) At what height, in feet, is the object \(2\) seconds after it reaches its maximum height?

A. 6
B. 86
C. 134
D. 150
E. 214

Answer: B

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