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Probability

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by swerve » Wed Apr 15, 2020 3:05 pm

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Answers

A

B

C

D

E

Stats

Difficulty—

At a certain amateur bands rock show the ratio of freaks to nerds to geeks is 1:2:3. If these are the only types of people in the crowd, and each person in the crowd has the same chance of yelling "rock on!", what are the chances that the next person who yells "rock on!" will be a geek?

A. 1/6
B. 1/3
C. 1/2
D. 2/3
E. 5/6

The OA is C

Source: Economist GMAT
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Re: Probability

by Jay@ManhattanReview » Thu Apr 16, 2020 12:38 am
swerve wrote: ↑
Wed Apr 15, 2020 3:05 pm
 At a certain amateur bands rock show the ratio of freaks to nerds to geeks is 1 : 2 : 3. If these are the only types of people in the crowd, and each person in the crowd has the same chance of yelling "rock on!", what are the chances that the next person who yells "rock on!" will be a geek?

A. 1/6
B. 1/3
C. 1/2
D. 2/3
E. 5/6

The OA is C

Source: Economist GMAT
Given that the ratio of freaks to nerds to geeks is 1 : 2 : 3, say the no. of freaks = x, no. of nerds = 2x, and no. of geeks = 3x; thus, the total no. of people in the crowd = 6x

=> the chances that the next person who yells "rock on!" will be a geek = 3x/6x = 1/2

The correct answer: C

Hope this helps!

-Jay
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Re: Probability

by Scott@TargetTestPrep » Mon Apr 27, 2020 3:19 am
swerve wrote: ↑
Wed Apr 15, 2020 3:05 pm
 At a certain amateur bands rock show the ratio of freaks to nerds to geeks is 1:2:3. If these are the only types of people in the crowd, and each person in the crowd has the same chance of yelling "rock on!", what are the chances that the next person who yells "rock on!" will be a geek?

A. 1/6
B. 1/3
C. 1/2
D. 2/3
E. 5/6

The OA is C

Source: Economist GMAT
The probability is 3/(1 + 2 + 3) = 3/6 = 1/2.

Answer: C

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