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What is the median of set A {-8, 15, -9, 4, N}? (1) N is a p

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by Anaira Mitch » Sat Dec 10, 2016 11:04 am
What is the median of set A {-8, 15, -9, 4, N}?
(1) N is a prime and N^6 is even
(2) 2N + 14 < 20

I am stuck with above problem OA says A but I think both statements are sufficient. Please guide.
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Source: — Data Sufficiency |

by ceilidh.erickson » Sat Dec 10, 2016 11:35 am
DS questions about MEDIANS are relatively common. The best strategy is often to test cases.

What is the median of set A {-8, 15, -9, 4, N}?

First, put the known terms in order: [-9, -8, 4, 15]. There are several possibilities for what the median could be:

- if N</= -8, then -8 will be the median: [N, -9, -8, 4, 15]

- if N >/= 4, then 4 will be the median: [-9, -8, 4, N, 15]

- if N is between -8 and 4, N itself will be the median: [-9, -8, N, 4, 15]

In the first 2 cases, knowing either the value of N or simply the range of N would be sufficient to tell us the value of the median. In the 3rd case, we would have to know the value of N itself.

(1) N is a prime and N^6 is even
If some power of N is even, then N itself must be even. If it is also prime, then N = 2 (the only even prime). This is sufficient: the median must be 2.

(2) 2N + 14 < 20
Simplify:
2N < 6
N < 3

If N < 3, it might also be less than -8, making -8 the median. Or it might be the -8 < N < 3, in which case N is the median (of unknown value). This is insufficient to tell us the value of the median.

The answer is A.
Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education
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by [email protected] » Sat Dec 10, 2016 1:03 pm
Hi Anaira Mitch,

When reviewing questions, or if you're stuck on a question, it helps to define the 'work' that you've done so far. You think that Face 2 is sufficient, but you haven't stated WHY you think that.

We have a set of 5 values: -9, -8, 4, 15 and N (but we don't know what N is... it could be really big, really small, a duplicate of one of the numbers that's already there, some other number, etc.). We're asked for the MEDIAN of that group.

2) 2N + 14 < 20

We can simplify this Fact...

2N < 6
N < 3

IF....
N = 2, then the group is -9, -8, 2, 4 and 15 and the median = 2

IF....
N = -8, then the group is -9, -8, -8, 4 and 15 and the median = -8
Fact 2 is INSUFFICIENT

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
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by Jay@ManhattanReview » Thu Dec 15, 2016 1:25 am
Anaira Mitch wrote:What is the median of set A {-8, 15, -9, 4, N}?
(1) N is a prime and N^6 is even
(2) 2N + 14 < 20

I am stuck with above problem OA says A but I think both statements are sufficient. Please guide.
Hi Anaira,

S2 is not sufficient.

We know that 2N + 14 < 20 => N < 3. N can be any number 2, 1, 0, 1/2, -10, etc. The question does not state that N in an integer. Though S1 implies that N is an integer, we must forget S1 and focus only on S2.

Let us arrange the four known terms in ascending order: {-9, -8, 4, 15}

N can be in the following three places, rendering no unique value of median; {-9, -8, N, 4, 15}, {-9, N, -8, 4, 15}, and {N, -9, -8, 4, 15}. Insufficient.

-Jay

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