Let's take each statement one by one.VJesus12 wrote:Is x^2 + 9 prime?
(1) x is odd
(2) 3 ≤ x ≤ 7
[spoiler]OA=A[/spoiler]
Source: Veritas Prep
(1) x is odd
So, we have x^2 + 9 => (Odd)^2 + 9 => Odd + Odd = Even > 9.
Note that all prime numbers greater than 2 are odd, thus, x^2 + 9 is not a prime number. Sufficient.
(2) 3 ≤ x ≤ 7
We must not assume that x is an integer and can take only 3, 4, 5, 6, and 7 as values. This can happen if you have a hangover of Statement 1.
So, x can take any value within 3 ≤ x ≤ 7.
Say x^2 + 9 = 23 a prime number
Thus, x^2 = 23 - 9 = 14 => x = √14 = 3... The value of x lies within 3 ≤ x ≤ 7. The answer is Yes, x is a prime number.
However, if x = 3, then 3 ≤ x ≤ 7 => x^2 + 9 = 3^2 + 9 = 9 + 9 = 18, not a prime number. The answer is No, x is not a prime number.
Insufficient.
The correct answer: A
Hope this helps!
-Jay
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