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If \(k\ne 0\) and \(k-\dfrac{3-2k^2}{k}=\dfrac{x}{k},\) then \(x =\)
(A) \(-3 - k^2\)
(B) \(k^2 -3\)
(C) \(3k^2 - 3\)
(D) \(k - 3 - 2k^2\)
(E) \(k - 3 + 2k^2\)
Answer: C
Source: Official Guide
(A) \(-3 - k^2\)
(B) \(k^2 -3\)
(C) \(3k^2 - 3\)
(D) \(k - 3 - 2k^2\)
(E) \(k - 3 + 2k^2\)
Answer: C
Source: Official Guide
