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A line that passes through (–1, –4) and (3, k) has a slo

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by Scott@TargetTestPrep » Sun May 12, 2019 6:11 pm
Gmat_mission wrote:A line that passes through (-1, -4) and (3, k) has a slope = k. What is the value of k?

(A) 3/4
(B) 1
(C) 4/3
(D) 2
(E) 7/2

[spoiler]OA=C[/spoiler]

Source: Magoosh
We can use the slope formula:

[(k - (-4)]/(3 - (-1)) = k

(k + 4)/4 = k

k + 4 = 4k

4 = 3k

4/3 = k

Answer: C

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by Brent@GMATPrepNow » Mon May 13, 2019 4:37 am
Gmat_mission wrote:A line that passes through (-1, -4) and (3, k) has a slope = k. What is the value of k?

(A) 3/4
(B) 1
(C) 4/3
(D) 2
(E) 7/2
Slope of line between the points (x1, y1) and (x2, y2) = (y2 - y1)/(x2 - x1)
So, we can write: k = [k - (-4)]/[3 - (-1)]
Simplify: (k + 4)/4 = k
Multiply both sides by 4 to get: k + 4 = 4k
Subtract k from both sides to get: 4 = 3k
Divide both sides by 3 to get: 4/3 = k

Answer: C

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Brent
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