Let's take each statement one by one.VJesus12 wrote:Is \(x > 1?\)
(1) \(x^3 > x\)
(2) \(x^2 > x > 0\)
[spoiler]OA=B[/spoiler]
Source: Veritas Prep
(1) \(x^3 > x\)
Case 1: Say x = 2 < 1, then we see that 2^3 > 2. The answer is no.
Case 2: Say x = -1/2 > 1, then we see that (-1/2)^3 > -1/2 => -1/8 > -1/2. The answer is yes.
No unique answer. Insufficient.
(2) \(x^2 > x > 0\)
This is possible only if x > 1. Sufficient.
The correct answer: B
Hope this helps!
-Jay
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