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At the beginning of the year, the ratio of juniors to seniors in high school \(X\) was 3 to 4. During the year, 10 junio

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At the beginning of the year, the ratio of juniors to seniors in high school \(X\) was 3 to 4. During the year, 10 junio

by Vincen » Mon May 18, 2020 6:37 am

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At the beginning of the year, the ratio of juniors to seniors in high school \(X\) was 3 to 4. During the year, 10 juniors and twice as many seniors transferred to another high school, while no new students joined high school \(X.\) If, at the end of the year, the ratio of juniors to seniors was 4 to 5, how many seniors were there in high school \(X\) at the beginning of the year?

A. 80
B. 90
C. 100
D. 110
E. 120

[spoiler]OA=E[/spoiler]

Source: Manhattan GMAT
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Re: At the beginning of the year, the ratio of juniors to seniors in high school \(X\) was 3 to 4. During the year, 10 j

by deloitte247 » Sat May 23, 2020 12:15 am
Let the total number of juniors = j, and seniors = s at the beginning of the year
Therefore, j : s = 3 : 4 j/s = 3/4
=> j = 3/4(s)...........eqn 1

During the year :
(j - 10) : (s - 20) = 4 : 5
$$\frac{\left(j-10\right)}{\left(s-20\right)}=\frac{4}{5}$$
5(j-10)= 4(s-20) where j = 3/4(s) from equation 1
5 [3/4(s) - 10 ] = 4 (s - 20)
$$\frac{15}{4}\left(s\right)-50=45-80$$
$$\frac{15}{4}\left(s\right)-\frac{4s}{1}=-80+50$$
$$\frac{15s-165}{4}=-30$$
$$15s-165=-30\cdot4$$
$$\frac{-1s}{-1}=\frac{-120}{-1}$$
$$s=120$$

Answer = E
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Re: At the beginning of the year, the ratio of juniors to seniors in high school \(X\) was 3 to 4. During the year, 10 j

by swerve » Sat May 23, 2020 10:23 am
Vincen wrote: ↑
Mon May 18, 2020 6:37 am
 At the beginning of the year, the ratio of juniors to seniors in high school \(X\) was 3 to 4. During the year, 10 juniors and twice as many seniors transferred to another high school, while no new students joined high school \(X.\) If, at the end of the year, the ratio of juniors to seniors was 4 to 5, how many seniors were there in high school \(X\) at the beginning of the year?

A. 80
B. 90
C. 100
D. 110
E. 120

[spoiler]OA=E[/spoiler]

Source: Manhattan GMAT
\begin{array}{|c|c|}
\hline
\text{Juniors} & \text{Seniors} \\ \hline
3x & 4x \text{(Initially)} \\ \hline
\end{array}
After transfers
\begin{array}{|c|c|}
\hline
\text{Juniors} & \text{Seniors} \\ \hline
3x-10 & 4x-20 \\ \hline
\end{array}

Given that new ratio \(=\dfrac{3x−10}{4x−20}=\dfrac{4}{5}\quad \Rightarrow\quad x=30\)

Seniors initially \(= 120\)

Therefore, E
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Re: At the beginning of the year, the ratio of juniors to seniors in high school \(X\) was 3 to 4. During the year, 10 j

by Scott@TargetTestPrep » Sat May 30, 2020 1:47 pm
Vincen wrote: ↑
Mon May 18, 2020 6:37 am
 At the beginning of the year, the ratio of juniors to seniors in high school \(X\) was 3 to 4. During the year, 10 juniors and twice as many seniors transferred to another high school, while no new students joined high school \(X.\) If, at the end of the year, the ratio of juniors to seniors was 4 to 5, how many seniors were there in high school \(X\) at the beginning of the year?

A. 80
B. 90
C. 100
D. 110
E. 120

[spoiler]OA=E[/spoiler]

Solution:

We are given that the original ratio of juniors to seniors was 3x : 4x.

Since 10 juniors and 2(10) = 20 seniors transferred, we have a new ratio of 4 : 5. Thus:

(3x - 10)/(4x - 20) = 4/5

5(3x - 10) = 4(4x - 20)

15x - 50 = 16x - 80

30 = x

Thus, there were 4(30) = 120 seniors at the school at the beginning of the year.

Answer: E

Scott Woodbury-Stewart
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[email protected]

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