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Two thirds of the roads from A to B are at least 5 miles

Expert replies
by BTGmoderatorDC » Sun Jul 29, 2018 1:08 am

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty—

Two thirds of the roads from A to B are at least 5 miles long, and 1/4 of the roads from B to C are at least 5 miles long. If you randomly pick a road from A to B and then randomly pick a road from B to C, what is the probability that at least one of the roads you pick is at least 5 miles long?
(A) 1/6
(B) 1/4
(C) 2/3
(D) 3/4
(E) 11/12
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Source: — Problem Solving |

by GMATGuruNY » Sun Jul 29, 2018 2:48 am
BTGmoderatorDC wrote:Two thirds of the roads from A to B are at least 5 miles long, and 1/4 of the roads from B to C are at least 5 miles long. If you randomly pick a road from A to B and then randomly pick a road from B to C, what is the probability that at least one of the roads you pick is at least 5 miles long?
(A) 1/6
(B) 1/4
(C) 2/3
(D) 3/4
(E) 11/12
P(at least one of the 2 selected roads is at least 5 miles long) = 1 - P(neither of the 2 selected roads is at least 5 miles long)

From A to B:
Since 2/3 of the roads are at least 5 miles long, 1/3 are not.
Thus, the probability of selecting a road that is not at least 5 miles long = 1/3.

From B to C:
Since 1/4 of the roads are at least 5 miles long, 3/4 are not.
Thus, the probability of selecting a road that is not at least 5 miles long = 3/4.

P(neither of the 2 selected roads is at least 5 miles long) = (1/3)(3/4) = 1/4.
Thus:
P(at least one of the 2 selected roads is at least 5 miles long) = 1 - 1/4 = 3/4.

The correct answer is D.
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by [email protected] » Sun Jul 29, 2018 3:27 pm
Hi All,

We're told that 2/3 of the roads from A to B are at least 5 miles long, and 1/4 of the roads from B to C are at least 5 miles long. We're asked if you randomly pick a road from A to B and then randomly pick a road from B to C, what is the probability that AT LEAST one of the roads you pick is at least 5 miles long.

In these types of probability questions, it's often easiest to calculate the probability of what you DON'T WANT (and then subtract that from 1 to get the probability of what you DO want); Mitch's approach showcased that math. You can calculate the various ways to 'fit' what you DO want though - although it will be a bit more work (and in certain questions, it would be a lot more work).

There would be 3 ways for AT LEAST one of the two roads being at least 5 miles long:
1) First road IS, second road ISN'T
2) First road ISN'T, second road IS
3) Both roads ARE

The individual probabilities of those three events are:
1) (2/3)(3/4) = 6/12
2) (1/3)(1/4) = 1/12
3) (2/3)(1/4) = 2/12
Total probability = 6/12 + 1 /12 + 2/12 = 9/12 = 3/4

Final Answer: D

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by Jeff@TargetTestPrep » Sat Aug 18, 2018 7:02 pm
BTGmoderatorDC wrote:Two thirds of the roads from A to B are at least 5 miles long, and 1/4 of the roads from B to C are at least 5 miles long. If you randomly pick a road from A to B and then randomly pick a road from B to C, what is the probability that at least one of the roads you pick is at least 5 miles long?
(A) 1/6
(B) 1/4
(C) 2/3
(D) 3/4
(E) 11/12
The only way that you won't pick a road that is at least 5 miles long is if you pick a road from A to B that is less than 5 miles long and you also pick a road from B to C that is less than 5 miles long. The probability of the former is â…“, and the probability of the latter is 3/4. Therefore, the probability of picking no roads that are at least 5 miles long is 1/3 x 3/4 = 1/4. In other words, the probability of picking at least one road that is at least 5 miles long is 1 - 1/4 = 3/4.

Answer: D

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[email protected]

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