Is 20 the average (arithmetic mean) of a, b, and 20 ?

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BTGModeratorVI wrote:
Thu Jul 23, 2020 6:28 am
Is 20 the average (arithmetic mean) of a, b, and 20 ?

(1) a + b = 40
(2) a – b = 2

Answer: A
Source: GMAT prep
Target question: Is 20 the average (arithmetic mean) of a, b, and 20 ?
This is a good candidate for rephrasing the target question.
First recognize that we can write: Does (a + b + 20)/3 = 20 ?
Multiply both sides of that equation by 3 to get: Does a + b + 20 = 60 ?
Subtract 20 from both sides to get: Does a + b = 40 ?
REPHRASED target question: Does a + b = 40 ?

Aside: Here’s a video with tips on rephrasing the target question: https://www.gmatprepnow.com/module/gmat- ... cy?id=1100

Statement 1: a + b = 40
Perfect!!
The answer to the REPHRASED target question is YES, a + b = 40
Since we can answer the REPHRASED target question with certainty, statement 1 is SUFFICIENT

Statement 2: a – b = 2
Since we can not use this information to answer the REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT

If you aren't convinced, check out the following two cases:
Case a: a = 4 and b = 2 (this satisfies the condition that a - b = 2). In this case, the answer to the REPHRASED target question is NO, a + b does not equal 40
Case b: a = 21 and b = 19 (this also satisfies the condition that a - b = 2). In this case, the answer to the REPHRASED target question is YES, a + b = 40
Since we cannot answer the REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT

Answer: A

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BTGModeratorVI wrote:
Thu Jul 23, 2020 6:28 am
Is 20 the average (arithmetic mean) of a, b, and 20 ?

(1) a + b = 40
(2) a – b = 2

Answer: A
Source: GMAT prep
Statement 1: \(a + b = 40\)

\(a+ b+ 20 = 40+20 = 60\), thus average \(= \dfrac{60}{3} = 20\). Sufficient \(\Large{\color{green}\checkmark}\)

Statement 2: \(a – b = 2\)

We cannot calculate the values of \(a, b\) or the sum of \(a \& b\), so this statement is clearly insufficient.
We can only assume the values: \(a =21, b =19\), which would make the statement true, but \(a \& b\) could be anything, so an incomplete statement. Insufficient \(\Large{\color{red}\chi}\)

Therefore, A