Linda and Angela contract to paint a neighbor's house. Even though Linda spends 50% more time painting the house than Angela, each receives a payment of m dollars when the work is completed. If Angela decides to pay Linda n dollars so that they would have received the same compensation per hour worked, what is n in terms of m?
A. 1/2 m
B. 1/3 m
C. 1/4 m
D. 1/5 m
E. 1/6 m
The OA is D.
Can I say, Angela's time = t and Linda's time = 1.5t
Angela receives = m - n.
Linda receives = m + n.
Then,
$$\frac{(m+n)}{1.5t}=\frac{(m-n)}{t}\ \Rightarrow n=\frac{1}{5}m$$
Is there a strategic approach to this PS question? Can any experts help, please?
A. 1/2 m
B. 1/3 m
C. 1/4 m
D. 1/5 m
E. 1/6 m
The OA is D.
Can I say, Angela's time = t and Linda's time = 1.5t
Angela receives = m - n.
Linda receives = m + n.
Then,
$$\frac{(m+n)}{1.5t}=\frac{(m-n)}{t}\ \Rightarrow n=\frac{1}{5}m$$
Is there a strategic approach to this PS question? Can any experts help, please?













