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If \(x\) is negative and \(y\) is positive, what is the value of \(x\) given that \(x^2-8xy+16y^2=49?\)

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If \(x\) is negative and \(y\) is positive, what is the value of \(x\) given that \(x^2-8xy+16y^2=49?\)

by Vincen » Wed Oct 06, 2021 5:42 am

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If \(x\) is negative and \(y\) is positive, what is the value of \(x\) given that \(x^2-8xy+16y^2=49?\)

A. \(4y - 49\)
B. \(49 - 4y\)
C. \(-7 - 4y\)
D. \(7 + 4y\)
E. \(4y - 7\)

Answer: E

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