Hi-
What is the average ( arithmetic mean) of eleven consecutive integers?
1) The average of the first nine integers is 7
2) The average of the last nine integers is 9
With statement 1, the sum is 63, so I think there is a way for 9 consecutive integers to be = to 63, but I dont know will there be more than 1 way, ends up 3+4+5+6+7+8+9+10+11 will get me that, then I know the average as I know what are the two remaining number. For statement 2, the sum is 81, so there is a way to have the consecutive integers to be 81, but same as statement 1, I dont know if there is only one way to do so. Then, I ran out of time so I had to make a guess. The answer is D each statement alone is sufficient.
Is there a faster way to do this? Thanks in advance.
What is the average ( arithmetic mean) of eleven consecutive integers?
1) The average of the first nine integers is 7
2) The average of the last nine integers is 9
With statement 1, the sum is 63, so I think there is a way for 9 consecutive integers to be = to 63, but I dont know will there be more than 1 way, ends up 3+4+5+6+7+8+9+10+11 will get me that, then I know the average as I know what are the two remaining number. For statement 2, the sum is 81, so there is a way to have the consecutive integers to be 81, but same as statement 1, I dont know if there is only one way to do so. Then, I ran out of time so I had to make a guess. The answer is D each statement alone is sufficient.
Is there a faster way to do this? Thanks in advance.













