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In a certain class, the ratio of girls to boys is 5:4. How many girls are there?

Expert replies
by BTGModeratorVI » Tue Mar 10, 2020 7:26 am

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A

B

C

D

E

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Difficulty—

In a certain class, the ratio of girls to boys is 5:4. How many girls are there?

(1) If four new boys joined the class, the number of boys would increase by 20%.
(2) If the number of girls increases by 50%, then after such an increase, the probability that a randomly chosen student would be a boy would be 8/23

Answer: A
Source: Magoosh
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Source: — Data Sufficiency |

BTGModeratorVI wrote: ↑
Tue Mar 10, 2020 7:26 am
In a certain class, the ratio of girls to boys is 5:4. How many girls are there?

(1) If four new boys joined the class, the number of boys would increase by 20%.
(2) If the number of girls increases by 50%, then after such an increase, the probability that a randomly chosen student would be a boy would be 8/23

Answer: A
Source: Magoosh
1) \(\dfrac{G}{B} = \dfrac{5}{4}\).
\(4x + 4 = 1.2 \cdot 4x\)
You can find \(x\) and hence ans. \(\Large{\color{green}\checkmark}\)

2) \(\dfrac{8}{23} = \dfrac{4x}{9x +2.5x}\) \(x\) will cancel. \(\Large{\color{red}\chi}\)

So, only A stands.
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BTGModeratorVI wrote: ↑
Tue Mar 10, 2020 7:26 am
In a certain class, the ratio of girls to boys is 5:4. How many girls are there?

(1) If four new boys joined the class, the number of boys would increase by 20%.
(2) If the number of girls increases by 50%, then after such an increase, the probability that a randomly chosen student would be a boy would be 8/23

Answer: A
Source: Magoosh
Given: In a certain class, the ratio of girls to boys is 5:4.
Let G = number of girls in the class
Let B = number of boys in the class
We can write: G/B = 5/4
Cross multiply to get: 4G = 5B
Rearrange to get: 4G - 5B = 0

Target question: What is the value of G

Statement 1: If four new boys joined the class, the number of boys would increase by 20%.
Here's a word equation for this statement: (new boy population with 4 extra boys) = (old boy population increased by 20%)
In other words: B + 4 = B + (20% of B)
Or: B + 4 = B + 0.2B
Or: B + 4 = 1.2B
Subtract B from both sides: 4 = 0.2B
Solve: B = 4/(0.2) = 40/2 = 20
Once we know that B = 20, we can take 4G - 5B = 0 and plug in B = 20
We get: 4G - 5(20) = 0
Solve to get G = 25
The answer to the target question is G = 25
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: If the number of girls increases by 50%, then after such an increase, the probability that a randomly chosen student would be a boy would be 8/23
So, 1.5G = the NEW number of girls
B = the number of boys
So, 1.5G + B = the NEW number of children.
So, P(selected child is a boy) = B/(1.5G + B)
We're told the probability is 8/23
So, we can write: B/(1.5G + B) = 8/23
Cross multiply to get: 8(1.5G + B) = 23B
Expand to get: 12G + 8B = 23B
Subtract 23B from both sides to get: 12G - 15B
Divide both sides by 3 to get: 4G - 5B = 0
Hmmm, we ALREADY knew that 4G - 5B = 0
So, statement 2 does NOT add any new information.
As such, statement 2 is NOT SUFFICIENT

Answer: A

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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