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700+ spoiled apples

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by munaf » Wed Dec 09, 2009 5:44 am
16) A basket has 5 apples, one is spoiled. If Henry picked 2 apples simultaneously and at random, what is probability that the 2 selected apples will include the spoiled one.
a. 1�5
b. 2�10
c. 2�5
d. 1�2
e. 3�5
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by papgust » Wed Dec 09, 2009 7:31 am
Total number of ways of selecting 2 apples is 5C2 = 10

Of which, one is rotten. This means that out of 4 apples there is a rotten fruit (There is 1 good apple out of 2 selected apples). That means, total ways of having a spoiled fruit is 4.

Probability that 2 selected apples will include a spoiled one is 4/10 = 2/5 (Choice C)
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by munaf » Wed Dec 09, 2009 11:12 pm
How you got 4 in the numerator..some one please explain.
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by sadullaevd » Wed Dec 09, 2009 11:45 pm
OA plz?
Stay skeptical,
Think critically,
Assume nothing.
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by munaf » Thu Dec 10, 2009 12:09 am
OA- C
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by AVRMBA » Thu Dec 10, 2009 2:19 am
Hi Munaf,

Here as per my understanding this question can be solved in this way:

Henry picks 2 apples from 5 apples in the basket so total possible ways is:5c2= 10.

Possibility that 2 selected apples include spoiled one is (Probality of getting one spolied one + Probability of getting one good one from the 4 apples)

this probability will be 1 + 4c1 = 5

Hence the probability of getting one spoiled among the two apples picked randomly is 5/10 = 1/2.

Rgds,
AVR.
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by papgust » Thu Dec 10, 2009 2:25 am
munaf wrote:How you got 4 in the numerator..some one please explain.
You select 2 apples out of 5. Out of those 2, 1 is a good fruit. The other is the rotten fruit.

Number of ways of choosing that rotten fruit is 4C1 = 4 (No. of ways to select a rotten fruit out of 4 apples. We are not taking the 5th apple into account because we have already chosen that 5th fresh apple)

I hope this is clear!
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by qazpt » Thu Dec 10, 2009 3:10 pm
Try this way. 1 minus the chance of getting no rotten apples

1)chance of getting no rotten apples
1 1st chance is 4/5
2nd chance is 3/4

then multiply (3/4)(4/5) = 12/20

1- (12/20) = 8/20 (chance of not getting a rotten apple) =4/10 = 2/5
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by munaf » Sun Dec 13, 2009 3:20 am
Thanks Guys!!
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by maihuna » Sun Dec 13, 2009 9:43 am
munaf wrote:16) A basket has 5 apples, one is spoiled. If Henry picked 2 apples simultaneously and at random, what is probability that the 2 selected apples will include the spoiled one.
a. 1�5
b. 2�10
c. 2�5
d. 1�2
e. 3�5
Simultaneously doen't mean anything: Out of 2-picks one should be spoiled one: can be done in : 2*(4/5)*(1/4) = 2/5
Charged up again to beat the beast :)
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by homersimpson » Fri Dec 18, 2009 11:04 pm
This should be as stated in many posts above:
(1C1 x 4C1)/ 5C2

1C1 = number of ways you can take out one rotten apple
4C1 = number of ways you can take out one fresh apple out of 4
5C2 = number of ways you can take out 2 apples out of 5.

Cheers
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