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by vinviper1 » Mon Jun 09, 2008 7:55 pm
bumpy di bump
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by leovonp » Tue Jun 10, 2008 2:38 pm
Statement (1) --> 75 - 41 = 35 Now you can subdivide these any way you want as the q-stem did not give a lot of restrictions. Insufficient.

Statement (2) --> is even more vague. In terms of value added to the question you are close to zero. Insufficient.

Pick (e) with a light conscience.
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by Ian Stewart » Tue Jun 10, 2008 5:38 pm
leovonp wrote:Statement (1) --> 75 - 41 = 35 Now you can subdivide these any way you want as the q-stem did not give a lot of restrictions. Insufficient.

Statement (2) --> is even more vague. In terms of value added to the question you are close to zero. Insufficient.

Pick (e) with a light conscience.
Statement 1 is almost sufficient, actually.

-one country sent 41 representatives
-A sent the second greatest number of representatives
-each country sent a different number of representatives

We need to know: is it possible that A sent only 9 (or fewer) representatives?

Well, try to make the sum with A=9. There's only one way to do it: 9+8+7+6+4 = 34. The only way A can send fewer than 10 reps is if A sends exactly 9, and the remaining countries send 8, 7, 6 and 4. If the question had asked 'Did Country A send at least 9 representatives', or if the number in Statement 1 had been 39 instead of 41, the answer would be A, not E.
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by nishchal » Thu Jun 12, 2008 4:37 pm
(A) is insufficient because 75-41=34 reps can be divided into 5 other countries as 9,8,7,6,4 where 9 rep are from country A and similarly 34 rep can be divided into 11,6,7,9,1 where 11 reps are from country A. In both cases A has the second highest reps but we don't get definite answer to the question asked

(B) can be proven to be insufficient using the same numbers as above even though we shouldn't use the number 41 from choice (A). But it solves the purpose and shows that (B) alone is insufficient.

Using same numbers it can be proven that (A) and (B) are together insufficient as well. Hence (E) is the answer
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