If x = 0 and x = (8xy-16y^2)^.5
, then, in terms of y, x =
A. – 4y
B. y/4
C. y
D. 4y
E. 4y^2
OA: D
Please tell me why x=0 is given in the question.
I think i never used it while g\solving the problem for the correct answer.
, then, in terms of y, x =
A. – 4y
B. y/4
C. y
D. 4y
E. 4y^2
OA: D
Please tell me why x=0 is given in the question.
I think i never used it while g\solving the problem for the correct answer.
