BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

\(p\) is the smallest perfect cube greater than \(1\) such that the difference between the tens digit of \(p^2\) and the

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 2898
Joined: Thu Sep 07, 2017 2:49 pm
Thanked: 6 times
Followed by:5 members

\(p\) is the smallest perfect cube greater than \(1\) such that the difference between the tens digit of \(p^2\) and the

by Vincen » Sun Feb 14, 2021 11:49 am

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

\(p\) is the smallest perfect cube greater than \(1\) such that the difference between the tens digit of \(p^2\) and the units digit of \(p^2\) is \(2.\) If \(Z=1\cdot 2\cdot 3\cdot\cdots \cdot p,\) then the total number of factors of \(Z\) is

A. 5
B. 8
C. 14
D. 96
E. 192

Answer: D

Source: e-GMAT
Top
Source: — Problem Solving |
Post new topic Post Reply
• Page 1 of 1