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psm12se
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If xy > 0 does (x - 1)(y - 1) = 1?
(1) x + y = xy
(2) x = y
I solved this question and came out with answer as D but OA is A
Here is my approach
The question is asking whether (x-1)(y-1) = 1
so xy - x - y + 1 = 1
so xy = x + y ?
Statement 1: Says the same as the derived equation
Sufficient
Statement 2: x = y
substituted the values in the derived equation
x^2 = 2x
x^2 - 2x = 0
x(x-2) = 0
so x = 0 or x = 2
since xy > 0 so x = 2
Sufficient
Please let me know if the my approach is wrong here and how is statement 2 insufficient.
(1) x + y = xy
(2) x = y
I solved this question and came out with answer as D but OA is A
Here is my approach
The question is asking whether (x-1)(y-1) = 1
so xy - x - y + 1 = 1
so xy = x + y ?
Statement 1: Says the same as the derived equation
Sufficient
Statement 2: x = y
substituted the values in the derived equation
x^2 = 2x
x^2 - 2x = 0
x(x-2) = 0
so x = 0 or x = 2
since xy > 0 so x = 2
Sufficient
Please let me know if the my approach is wrong here and how is statement 2 insufficient.













