GEOMETRY - TRIANGLES

This topic has expert replies
User avatar
Master | Next Rank: 500 Posts
Posts: 228
Joined: Sun Jun 29, 2008 8:47 pm
Thanked: 15 times
Followed by:1 members

GEOMETRY - TRIANGLES

by amitdgr » Wed Sep 17, 2008 10:01 pm
In triangle ABC, point X is the midpoint of side AC and point Y is the midpoint of side BC. If point R is the midpoint of line segment XC and if point S is the midpoint of line segment YC, what is the area of triangle region RCS

(1) the area of triangular region ABX is 32
(2) the length of one of the altitudes of triangle ABC is 8


No idea what the answer is...

[size=0]
apnew[/size]
Please visit my blog Gmat Tips and Strategies
Source: — Data Sufficiency |

Master | Next Rank: 500 Posts
Posts: 496
Joined: Sun May 04, 2008 11:01 pm
Location: mumbai
Thanked: 7 times
GMAT Score:640

by stubbornp » Wed Sep 17, 2008 10:14 pm
bcoz both are similar triangles...area should be one fourth of original..

stmt 1-correct...

stmt2-insufficient-

A

User avatar
Master | Next Rank: 500 Posts
Posts: 228
Joined: Sun Jun 29, 2008 8:47 pm
Thanked: 15 times
Followed by:1 members

by amitdgr » Wed Sep 17, 2008 10:38 pm
stubbornp wrote:bcoz both are similar triangles...area should be one fourth of original..

stmt 1-correct...

stmt2-insufficient-

A
which "both" are similar triangles ?

Thanks
Please visit my blog Gmat Tips and Strategies

Master | Next Rank: 500 Posts
Posts: 496
Joined: Sun May 04, 2008 11:01 pm
Location: mumbai
Thanked: 7 times
GMAT Score:640

by stubbornp » Wed Sep 17, 2008 10:45 pm
rsc and abc....

User avatar
Master | Next Rank: 500 Posts
Posts: 228
Joined: Sun Jun 29, 2008 8:47 pm
Thanked: 15 times
Followed by:1 members

by amitdgr » Thu Sep 18, 2008 1:24 am
But nowhere we are given the area of triangle ABC , And the question is asking for area of RCS
Please visit my blog Gmat Tips and Strategies

Legendary Member
Posts: 891
Joined: Sat Aug 16, 2008 4:21 am
Thanked: 27 times
Followed by:1 members
GMAT Score:660(

by 4meonly » Thu Sep 18, 2008 3:14 am
area of ∆ABC is twice the are of ∆ABX
height the same, base of ∆ABC is twice the base of ∆ABX

(1) the area of triangular region ABX is 32
we can find the area of ∆ABC, it is is twice the are of ∆ABX,
so area of ∆ABC is 64

sides of ∆ABC are 4 times the sides of ∆RSC
so the area of ∆ABC is 4^2=16 times more the the area of ∆RSC

64/16=4
the area of ∆RSC is 4

Answer A
Last edited by 4meonly on Thu Sep 18, 2008 10:53 pm, edited 2 times in total.

User avatar
Senior | Next Rank: 100 Posts
Posts: 55
Joined: Sun Sep 14, 2008 6:51 am
Location: Netherlands
Thanked: 10 times
GMAT Score:680

by tendays2go » Thu Sep 18, 2008 1:38 pm
correct and bravo 4meonly!
i missed the point that height is same for both ABX and ABC :(
(but, do explain this in the first post only...will save tiny li'l time :) )
hope i dont repeat this "slip" in the actual exam :O

User avatar
Master | Next Rank: 500 Posts
Posts: 228
Joined: Sun Jun 29, 2008 8:47 pm
Thanked: 15 times
Followed by:1 members

by amitdgr » Thu Sep 18, 2008 8:18 pm
Thanks for explanation 4meonly.

but median is not always the altitude except in equilateral or isoceles triangles, and we are not sure if the triangle at hand is equilateral or isoceles.

Am I missing something ?
Please visit my blog Gmat Tips and Strategies

Legendary Member
Posts: 891
Joined: Sat Aug 16, 2008 4:21 am
Thanked: 27 times
Followed by:1 members
GMAT Score:660(

by 4meonly » Thu Sep 18, 2008 10:49 pm
I hope this small picture will help to deal with any problems
Attachments
123.JPG

User avatar
Master | Next Rank: 500 Posts
Posts: 228
Joined: Sun Jun 29, 2008 8:47 pm
Thanked: 15 times
Followed by:1 members

by amitdgr » Thu Sep 18, 2008 11:14 pm
Thanks :) Things pretty clear now
Please visit my blog Gmat Tips and Strategies