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Cars and TVs

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Cars and TVs

by sampath » Thu Jul 28, 2011 10:34 am
Three thousand families live in a certain town. How many families who live in the town own neither a car nor a
television set?
(1) Of the families who live in the town, 2,980 own a car.
(2) Of the families who live in the town, 2,970 own both a car and a television set.

I got the answer as C. Could someone please confirm the answer. Thanks.
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Source: — Data Sufficiency |
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by GAMATO » Thu Jul 28, 2011 11:44 am
IMO E
sampath wrote:Three thousand families live in a certain town. How many families who live in the town own neither a car nor a
television set?
(1) Of the families who live in the town, 2,980 own a car.
(2) Of the families who live in the town, 2,970 own both a car and a television set.

I got the answer as C. Could someone please confirm the answer. Thanks.
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by HeintzC2 » Thu Jul 28, 2011 1:22 pm
Agreed, believe the correct solution is E

Statement (1) tells us 20 families in the town don't have a car.
Insufficient by itself.

Statement (2) tells us 30 families in the town don't have a car or a television set (could be one, the other, or both).
Insufficient by itself.

Statement (1) and (2) together tell us that out of the 30 families that don't have a car or a television set, there are 20 families that definitely do not have a car. We are not given any input on the number of families that don't own televisions, therefore, insufficient together.
GAMATO wrote:IMO E
sampath wrote:Three thousand families live in a certain town. How many families who live in the town own neither a car nor a
television set?
(1) Of the families who live in the town, 2,980 own a car.
(2) Of the families who live in the town, 2,970 own both a car and a television set.

I got the answer as C. Could someone please confirm the answer. Thanks.
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by ColumbiaVC » Fri Jul 29, 2011 4:59 pm
I got the answer as C.
Whats the OA???
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by edge » Fri Jul 29, 2011 5:32 pm
My answer is E.

The two statements are obviously insufficient by themselves. Combining the given information in the question and the two statements, we have:

n(Total) = n(cars only) + n(car and TV) + n(TV only) + n(neither car nor TV)
3000 = (2980 - 2970) + 2970 + n(TV only) + n(neither car nor TV)
n(neither car nor TV) = 20 - n(TV only)
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