BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Four different children have jelly beans: Aaron has 5, Bianca has 7, Callie has 8, and Dante has 11. How many...

Expert replies
by BTGmoderatorLU » Fri Mar 27, 2020 1:20 pm

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty

Manhattan Prep

Four different children have jelly beans: Aaron has 5, Bianca has 7, Callie has 8, and Dante has 11. How many jelly beans must Dante give to Aaron to ensure that no child has more than 1 fewer jelly beans than any other child?

A. 2
B. 3
C. 4
D. 5
E. 6

The OA is B
Join the discussion
Source: — Problem Solving |

Aaron = 5, Bianca = 7, Callie = 8, Dante = 11
How many jelly Bean must Dante give to Aaron to ensure that no child has more than one fewer Jelly bean than any other child .

Dante have to give out some of his Jelly bean.
Bianca and Callie already satisfy the condition which states that no child more than one fewer Jelly Bean than any other child.

Therefore, nobody should have more than 8 Jelly bean and less than 7 Jelly bean.
If Dante gives three Jelly bean to Aaron

Dante = 11-3 =8 and Aaron = 5+3

This satisfies all the condition in the question.
$$Answer\ \ is\ Option\ B$$
Dante has to give Jelly bean to Aaron .
Join the discussion

BTGmoderatorLU wrote:
Fri Mar 27, 2020 1:20 pm
Manhattan Prep

Four different children have jelly beans: Aaron has 5, Bianca has 7, Callie has 8, and Dante has 11. How many jelly beans must Dante give to Aaron to ensure that no child has more than 1 fewer jelly beans than any other child?

A. 2
B. 3
C. 4
D. 5
E. 6

The OA is B
Since Bianca’s number of jelly beans and Callie’s number of jelly beans differ by exactly 1, we need to bring Aaron’s number of jelly beans to either Bianca’s or Callie’s. If Aaron’s number is brought up to Bianca’s (i.e., Dante gives Aarron 2 jelly beans), then Aaron, Bianca, Callie, and Dante have 7, 7, 8, and 9 jelly beans, respectively. However, we see that Dante still has 2 more jelly beans than either Aaron or Bianca. On the other hand, if Aaron’s number is brought up to Callie’s (i.e., Dante gives Aarron 3 jelly beans), then Aaron, Bianca, Callie, and Dante have 8, 7, 8, and 8 jelly beans, respectively. We see that in this case, no child has more than 1 fewer jelly beans than any other child.

Answer: B

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Join the discussion