A chili recipe calls for the final mixture to consist of 1/2 meat and 1/3 beans, with the remainder an even mixture of

This topic has expert replies
Legendary Member
Posts: 2898
Joined: Thu Sep 07, 2017 2:49 pm
Thanked: 6 times
Followed by:5 members
A chili recipe calls for the final mixture to consist of 1/2 meat and 1/3 beans, with the remainder an even mixture of sauce and various spices. If a total of 6 pounds of sauce and spices are used, how many pounds of beans are used?

A. 3
B. 6
C. 12
D. 18
E. 24

[spoiler]OA=C[/spoiler]

Source: Veritas Prep
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770
Vincen wrote:
Sun Jun 14, 2020 3:51 am
A chili recipe calls for the final mixture to consist of 1/2 meat and 1/3 beans, with the remainder an even mixture of sauce and various spices. If a total of 6 pounds of sauce and spices are used, how many pounds of beans are used?

A. 3
B. 6
C. 12
D. 18
E. 24

[spoiler]OA=C[/spoiler]

Source: Veritas Prep
A chili recipe calls for the final mixture to consist of 1/2 meat and 1/3 beans, with the remainder an even mixture of sauce and various spices
Let's see what fraction of the final mixture is sauce and various spices
1/2 + 1/3 = 3/6 + 2/6 = 5/6
If 5/6 of the mixture is meat and beans, then the remaining 1/6 of the mixture is sauce and various spices

So, the mixture is 1/2 meat, 1/3 beans and 1/6 sauce and various spices

If a total of 6 pounds of sauce and spices are used, how many pounds of beans are used?
Notice that 1/3 is TWICE 1/6
This means the weight of beans in the mixture is TWICE the weight of sauce and spices in the mixture
So, if the mixture contains 6 pounds of sauce and spices, then it must contain 12 pounds of beans in the mixture

Answer: C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image