VJesus12 wrote:$$\frac{1}{3}+\frac{1}{2}−\ \frac{5}{6}+\frac{1}{5}+\frac{1}{4}−\ \frac{9}{20}=\ ?$$ $$(A)\ \ 0$$ $$(B)\ \ \ \frac{2}{15}$$ $$(C)\ \ \ \frac{2}{5}$$ $$(D)\ \frac{9}{20}$$ $$(E)\ \ \frac{5}{6}$$ The OA is A.
What is the best way to solve this PS question? May any expert give me some help? Thanks in advanced.
$$\frac{1}{3}+\frac{1}{2}−\ \frac{5}{6}+\frac{1}{5}+\frac{1}{4}−\ \frac{9}{20}=\ x$$
$$60(\frac{1}{3}+\frac{1}{2}−\ \frac{5}{6}+\frac{1}{5}+\frac{1}{4}−\ \frac{9}{20})=\ 60x$$
$$20+30-50+12+15-27 = 60x$$
$$0 = 60x$$
$$0 = x$$
The correct answer is
A.
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