nhai2003 wrote:It takes printer A 4 more minutes than printer B to print 40 pages. Working together, the two printers can print 50 pages in 6 minutes. How long will it take printer A to print 80 pages?
* 12
* 18
* 20
* 24
* 30
We have a combined worker problem for which we can use the following formula:
work ( machine 1) + work ( machine 2) = total work completed
We are given that it takes printer A 4 more minutes than printer B to print 40 pages. Recall that rate = work/time, and if we let the rate of printer B = 40/t, in which t is the time for printer B to print 40 pages, then the rate of printer A = 40/(t+4).
We are also given that working together the two printers can print 50 pages in 6 minutes.
Since work = rate x time, we can calculate the work done by each printer.
printer A work = 40/(t+4) x 6 = 240/(t+4)
printer B work = 40/t x 6 = 240/t
Since the two machines print 50 pages together, we can use that value in our combined work formula and determine t.
work (printer A) + work (printer B) = 50 pages
240/(t+4) + 240/t = 50
Multiplying the entire equation by t(t+4) gives us:
240t + 240(t+4) = 50t(t+4)
240t + 240t + 960 = 50t^2 + 200t
50t^2 - 280t - 960 = 0
5t^2 - 28t - 96 = 0
(5t + 12)(t - 8) = 0
t = -12/5 or t = 8
Since t can't be negative, t = 8. That is, it takes printer B 8 minutes to print 40 pages. Thus it will take printer A 12 minutes to print 40 pages and 24 minutes to print 80 pages (since 80 pages are twice as many as 40 pages).
Answer:
D