j_shreyans wrote:A driver paid n dollars for auto insurance for the year 1997. This annual premium was raised by p percent for the year 1998; for each of the years 1999 and 2000, the premium was decreased by 1/6 from the previous year's figure. If the driver's insurance premium for the year 2000 was again n dollars, what is the value of p?
A)12
B)100/3
C)36
D)44
E)50
Let n = 100.
We can PLUG IN THE THE ANSWERS, which represent the value of p.
When the correct answer choice is plugged in, the premium in 2000 = n = 100.
Answer choice
D: 44
Since the premium increases by p% in 1998, the premium in 1998 = 100 + 44% of 100 = 144.
Since the premium decreases by 1/6 in 1999, the premium in 1999 = 144 - (1/6)(144) = 144 - 24 = 120.
Since the premium deceases by another 1/6 in 2000, the premium in 2000 = 120 - (1/6)(120) = 120 - 20 = 100.
Success!
The correct answer is
D.
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