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Set S consist of the values 11, -9, 100, 0, x, and y. if x not equal to y, what is the median of the set S?

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Set S consist of the values 11, -9, 100, 0, x, and y. if x not equal to y, what is the median of the set S?

by BTGmoderatorDC » Tue Apr 06, 2021 11:48 pm

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Set S consist of the values 11, -9, 100, 0, x, and y. if x not equal to y, what is the median of the set S?

(1) The average (arithmetic mean) of X and Y is 308.
(2) The mode of Set S is 0.


OA C

Source: Veritas Prep
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Source: — Data Sufficiency |
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Re: Set S consist of the values 11, -9, 100, 0, x, and y. if x not equal to y, what is the median of the set S?

by swerve » Wed Apr 07, 2021 7:06 am

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BTGmoderatorDC wrote: ↑
Tue Apr 06, 2021 11:48 pm
 Set S consist of the values 11, -9, 100, 0, x, and y. if x not equal to y, what is the median of the set S?

(1) The average (arithmetic mean) of X and Y is 308.
(2) The mode of Set S is 0.


OA C

Source: Veritas Prep
Statement 1:
Mean of \(x\) and \(y\) is 308
\(x= 1\) and \(y = 30\)
\(-9, 0, 1, 11, 100, 307\) Median \(= 6\)
\(x = -2, y = 310\)
\(-9, -2, 0, 11, 100, 310\) Median \(= 5.5\) Not Sufficient. \(\Large{\color{red}\chi}\)

Statement 2:
Mode is \(0\)
\(x = 0, y =101\)
\(-9, 0, 0, 11, 100, 101\) Median \(= 5.5\)
\(x = 0, y = 3\)
\(-9, 0, 0, 3, 11, 100\) Median \(= 1.5\) Not Sufficient. \(\Large{\color{red}\chi}\)

Statement 1&2:
\(x = \dfrac{0}{308}, y = \dfrac{308}{0}\)
\(-9, 0, 0, 11, 100, 308\) Median \(= 5.5\) Sufficient. \(\Large{\color{green}\checkmark}\)

Therefore, C
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