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manjithmanohar
- Newbie | Next Rank: 10 Posts
- Posts: 3
- Joined: Wed Mar 25, 2009 4:50 am
The basic condition for the equation |x-z| + |x| = |z| to be true is that
|z| > |x|
The inequality zy < xy < 0
further implies that |z| > |x| where the y value could be both +/ - respectively to maintain the inequality. (I hope I don't need to elaborate this part)
So considering the answers:
1. z < x (if it is considered with the inequality both z and x are negative and that y is positive.) so proves |z| > |x|, hence true.
2. y < 0 (when fit into the inequality proves that again |z| > |x|) so true.
Answer most definitely is D.
Please feel free to discuss this!
|z| > |x|
The inequality zy < xy < 0
further implies that |z| > |x| where the y value could be both +/ - respectively to maintain the inequality. (I hope I don't need to elaborate this part)
So considering the answers:
1. z < x (if it is considered with the inequality both z and x are negative and that y is positive.) so proves |z| > |x|, hence true.
2. y < 0 (when fit into the inequality proves that again |z| > |x|) so true.
Answer most definitely is D.
Please feel free to discuss this!