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Expert replies
by sana.noor » Sun Jun 16, 2013 5:11 am
A and B ran a race of 480 m. In the first heat, A gives B a head start of 48 m and beats him by 1/10th of a minute. In the second heat, A gives B a head start of 144 m and is beaten by 1/30th of a minute. What is B's speed in m/s?
(A) 12
(B) 14
(C) 16
(D) 18
(E) 20

OA is A
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Source: — Problem Solving |

by Brent@GMATPrepNow » Sun Jun 16, 2013 5:55 am
sana.noor wrote:A and B ran a race of 480 m. In the first heat, A gives B a head start of 48 m and beats him by 1/10th of a minute. In the second heat, A gives B a head start of 144 m and is beaten by 1/30th of a minute. What is B's speed in m/s?
(A) 12
(B) 14
(C) 16
(D) 18
(E) 20

OA is A
Let A = A's speed in meters per second
Let B = B's speed in meters per second

A gives B a head start of 48 m and beats him by 1/10th of a minute.
1/10th of a minute = 6 seconds
A's travel time is 6 seconds less than B's travel time
So, (A's travel time) = (B's travel time) - 6

A traveled 480 meters and B traveled 432 meters.
Travel time = distance/speed, so . . .
(480/A) = (432/B) - 6

A gives B a head start of 144 m and is beaten by 1/30th of a minute.
1/30th of a minute = 2 seconds
A's travel time is 2 seconds more than B's travel time
So, (A's travel time) = (B's travel time) + 2

A traveled 480 meters and B traveled 336 meters.
Travel time = distance/speed, so . . .
(480/A) = (336/B) + 2

IMPORTANT: Since both equations are set equal to 480/A, we can set them equal to each other.
(432/B) - 6 = (336/B) + 2
Multiply both sides by B: 432 - 6B = 336 + 2B
Rearrange: 96 = 8B
Solve: B = 12

Answer: A

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Brent
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by GMATGuruNY » Sun Jun 16, 2013 1:34 pm
sana.noor wrote:A and B ran a race of 480 m. In the first heat, A gives B a head start of 48 m and beats him by 1/10th of a minute. In the second heat, A gives B a head start of 144 m and is beaten by 1/30th of a minute. What is B's speed in m/s?
(A) 12
(B) 14
(C) 16
(D) 18
(E) 20

OA is A
An alternate approach is to plug in the answers, which represent B's rate.
Since B's rate is almost certainly a factor of 480 -- the value of the distance -- the correct answer is probably A, C, or E.

In the first heat, A beats B by (1/10)*60 = 6 seconds.
In the second heat, B beats A by (1/30)*60 = 2 seconds.

Answer choice C: B = 16 meters per second.
First heat:
Time for B = d/r = 480/16 = 30 seconds.
Headstart given to A = 48/16 = 3 seconds.
Since A beats B by 6 seconds, total time for A = 30-(3+6) = 21 seconds.
21 is not a factor of 480.
Eliminate C.

Answer choice A: B = 12 meters per second.
First heat:
Time for B = d/r = 480/12 = 40 seconds.
Headstart given to A = 48/12 = 4 seconds.
Since A beats B by 6 seconds, total time for A = 40-(4+6) = 30 seconds.
Rate for A = d/t = 480/30 = 16 meters per second.

Second heat:
Headstart given to B = 144/12 = 12 seconds.
From the first heat: Time for B - Time for A = 40-30 = 10 seconds.
Since B is given a 12-second headstart, and the time for A is only 10 seconds less than the time for B, B beats A by 12-10 = 2 seconds.
Success!

The correct answer is A.

Algebracially:

Let A = A's rate and B = B's rate.

A gives B a head start of 48 meters:
After the head start, the distance traveled by B = 480-48 = 432 meters.
A travels the entire distance.
Time for A to travel 480 meters = 480/A.
Time for B to travel 432 meters = 432/B.
A wins by 1/10 of a minute = 6 seconds.
In other words, the difference between B's time and A's time is 6 seconds:
432/B - 480/A = 6.

A gives B a head start of 144 meters:
After the head start, the distance traveled by B = 480-144 = 336 meters.
A travels the entire distance.
Time for A to travel 480 meters = 480/A.
Time for B to travel 336 meters = 336/B.
B wins by 1/30 of a minute = 2 seconds.
In other words, the difference between A's time and B's time is 2 seconds:
480/A - 336/B = 2.

Adding the two equations, we get:
(432/B - 480/A) + (480/A - 336/B) = 6+2
96/B = 8
B = 12.
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by sana.noor » Tue Jun 18, 2013 11:29 pm
Thanks Brent and Mitch
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