What is the value of 2x/3y?

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What is the value of 2x/3y?

by M7MBA » Wed Jun 06, 2018 12:59 am

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What is the value of 2x/3y?

(1) x^2/y^2 = 36/25
(2) x^5/y^5 > 1

The OA is the option C.

How can I use both statements to get an answer here? May anyone give me some help? Please.
Source: — Data Sufficiency |

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by [email protected] » Wed Jun 06, 2018 8:41 pm

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Hi All,

We're asked for the value of 2X/3Y. This question can be solved by TESTing VALUES.

1) (X^2)/(Y^2) = 36/25

IF....
X=6, Y=5, then the answer to the question is 12/15 = 4/5
X=6, Y= -5, then the answer to the question is 12/-15 = -4/5
Fact 1 is INSUFFICIENT

2) X^5/Y^5 > 1

With this inequality, we know that X and Y must be the SAME sign (either both positive or both negative).

IF....
X=6, Y=5, then the answer to the question is 12/15 = 4/5
X=6, Y=1, then the answer to the question is 12/3 = 4
Fact 2 is INSUFFICIENT

Combined, we know...
(X^2)/(Y^2) = 36/25
X^5/Y^5 > 1

Since X and Y must be the SAME sign, we have two immediate examples that 'fit' both Facts....
IF....
X=6, Y=5, then the answer to the question is 12/15 = 4/5
X= -6, Y= -5, then the answer to the question is -12/-15 = 4/5

X and Y could be other values though, but the only pairs of values that fit the first equation will be in the ratio of 6:5. For example....
IF....
X=12, Y=10, then the answer to the question is 24/30 = 4/5
X= -12, Y= -10, then the answer to the question is -24/-30 = 4/5
The answer will ALWAYS be 4/5.
Combined, SUFFICIENT

Final Answer: C

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