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Que: A juice manufacturer has 1,200 liters of mango pulp in stock, 25 percent of which is water.

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by Max@Math Revolution » Thu Nov 26, 2020 2:14 am

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Que: A juice manufacturer has 1,200 liters of mango pulp in stock, 25 percent of which is water. If the manufacturer adds another 400 liters of mango pulp of which 20 percent is water, what percent, by volume, of the manufacturer’s mango pulp contains water?

(A) 21.50%
(B) 23.75%
(C) 33.33%
(D) 35.00%
(E) 37.50%
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Re: Que: A juice manufacturer has 1,200 liters of mango pulp in stock, 25 percent of which is water.

by Max@Math Revolution » Tue Dec 01, 2020 12:43 am
Solution: The resultant percentage will be the weighted average of the percentages of the above two stocks.

=> \(\frac{\left[\left(1200\cdot0.25\right)\ +\ \left(400\ \cdot\ 0.20\right)\right]}{\left[\left(1,200\ +\ 400\right)\right]}\cdot100\)

=> \(\frac{\left(300\ +\ 80\right)}{\left(1,600\ \right)}\cdot100\)

=> \(\frac{\left(380\right)}{\left(1,600\ \right)}\cdot100\) => 23.75%

Therefore, B is the correct answer.

Answer B
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Re: Que: A juice manufacturer has 1,200 liters of mango pulp in stock, 25 percent of which is water.

by Scott@TargetTestPrep » Wed Apr 21, 2021 6:15 am
Max@Math Revolution wrote: ↑
Thu Nov 26, 2020 2:14 am
 Que: A juice manufacturer has 1,200 liters of mango pulp in stock, 25 percent of which is water. If the manufacturer adds another 400 liters of mango pulp of which 20 percent is water, what percent, by volume, of the manufacturer’s mango pulp contains water?

(A) 21.50%
(B) 23.75%
(C) 33.33%
(D) 35.00%
(E) 37.50%
Solution:

The percentage of water in the mixed mango pulp is:

[(1200 x 0.25 + 400 x 0.2) / (1200 + 400)] x 100 = [(300 + 80) / 1600] x 100 = 380/16 = 23.75 percent

Answer: B

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