Velma has exactly one week to learn all $71$ Japanese hiragana characters. If she can learn at most a dozen of them

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AAPL: Moderator; Posts: 2644; Joined: Sun Oct 29, 2017 2:08 pmFollowed by: 2 members

by AAPL » Sat May 27, 2023 1:41 pm

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Velma has exactly one week to learn all $71$ Japanese hiragana characters. If she can learn at most a dozen of them on any one day and will only have time to learn four of them on Friday, what is the least number of hiragana that Velma will have to learn on Saturday?

A. $0$
B. $7$
C. $10$
D. $11$
E. $12$

OA B

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Source: Beat The GMAT — Problem Solving | Sat May 27, 2023 1:41 pm

GMATJourneyman: Junior | Next Rank: 30 Posts; Posts: 16; Joined: Wed May 24, 2023 7:40 am

Re: Velma has exactly one week to learn all $71$ Japanese hiragana characters. If she can learn at most a dozen of the

by GMATJourneyman » Sun May 28, 2023 8:43 am

AAPL wrote: ↑
Sat May 27, 2023 1:41 pm
Manhattan Prep

Velma has exactly one week to learn all $71$ Japanese hiragana characters. If she can learn at most a dozen of them on any one day and will only have time to learn four of them on Friday, what is the least number of hiragana that Velma will have to learn on Saturday?

A. $0$
B. $7$
C. $10$
D. $11$
E. $12$

OA B

Velma can learn at most 12 characters per day. In six days (excluding Friday), that's 6*12 = 72 characters. But she only needs to learn 71 characters in total, and she's learning 4 on Friday. So, she has 71 - 4 = 67 characters to learn in six days.

To minimize Saturday's load, she should maximize her learning on the other days, learning 12 characters each day. That's 5*12 = 60 characters.

Subtracting this from the 67 characters leaves 67 - 60 = 7 characters to learn on Saturday. So, Velma needs to learn at least 7 characters on Saturday.

Answer is B

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