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ps500 test25 #20

by dunkin77 » Wed Apr 18, 2007 11:53 am

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20. On the day of the performance of a certain play, each ticket that regularly sells for less than $10.00 is sold for half price plus $0.50, and each ticket that regularly sells for $10.00 or more is sold for half price plus $1.00. On the day of the performance, a person purchases a total of y tickets, of which x regularly sell for $9.00 each and the rest regularly sell for $12.00 each. What is the amount paid, in dollars, for the y tickets ?

(A) 7y - 2x
(B) 12x - 7y
(C) (9x+12) / 2
(D) 7y + 4x
(E) 7y + 5x


Hi,

The answer to this question is A) but can not figure out how to set an equation..... Can anyone please explain??

Thanks!!
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ps500 test25 #20

by gviren » Wed Apr 18, 2007 2:31 pm
I think the answer should be B - 12x-7y

x tickets for $9/2 + $0.5

y tickets for $12/2 + $1.0

so the total is $9/2x + $0.5x + $12/2 (x-y) + $1.0 (x-y)

= 5x + 7x - 7y
= 12x - 7y
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by dunkin77 » Wed Apr 18, 2007 3:11 pm
Hi,

I just checked the answer again, but it says "A" --- but then again, the answer in text could be wrong.

Can anyone please confirm the answer???
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by Ramesh2007 » Wed Apr 18, 2007 3:51 pm
x tickets:

regular price 9
sold price = x*9/2 + 0.5*x = 10*x/2 = 5x

y tickets:

regular price 12
sold price = 12*y/2 + 1*y = 6*y + y = 7y

total = 5x+7y

Option (E)

Can somebody confirm this.
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by Ramesh2007 » Wed Apr 18, 2007 3:53 pm
Just to clarify my reply above, the question says each ticket is sold at half the price + 0.5 for tickets less than 10$. So we need to multiply 0.5 with the number of tickets sold.
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by gviren » Wed Apr 18, 2007 8:03 pm
I think it should be B. I think I explianed it wrong (2nd part)

think the answer should be B - 12x-7y

x tickets for $9/2 + $0.5

x - y tickets for $12/2 + $1.0 (The remaining of y tickets after selling x at $9 )

so the total is $9/2x + $0.5x + $12/2 (x-y) + $1.0 (x-y)

= 5x + 7x - 7y
= 12x - 7y
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by Cybermusings » Thu Apr 19, 2007 1:40 am
x ---- regularly sell for $9 ---- or (4.5+.5) = $5 each ----- total = 5x
y-x ----- regularly sell for $12 ---- or (6+1) = $7 each ----- total = 7(y-x)
Hence total amount for y tickets = 5x + 7y - 7x = 7y - 2x
Hence A
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by leo » Thu Apr 19, 2007 7:22 am
X ticket cost = x*5 (9/2+.5)
remaining ticket cost = (y-x)*7(6+1)
total cost = 5x+7y-7x = 7y-2x.

Ans = A
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by Scott@TargetTestPrep » Mon Nov 12, 2018 7:27 am
dunkin77 wrote:20. On the day of the performance of a certain play, each ticket that regularly sells for less than $10.00 is sold for half price plus $0.50, and each ticket that regularly sells for $10.00 or more is sold for half price plus $1.00. On the day of the performance, a person purchases a total of y tickets, of which x regularly sell for $9.00 each and the rest regularly sell for $12.00 each. What is the amount paid, in dollars, for the y tickets ?

(A) 7y - 2x
(B) 12x - 7y
(C) (9x+12) / 2
(D) 7y + 4x
(E) 7y + 5x
Since x tickets are regularly sold for $9 each, now they are sold for 4.5 + 0.5 = $5 each. Thus, the cost of the x discounted tickets is 5x. Similarly, since the rest of the tickets, i.e., (y - x) tickets, are regularly sold for $12 each, now they are sold for 6 + 1 = $7 each. The cost of the (y - x) discounted tickets is 7(y - x). Therefore, the total amount, in dollars, paid for the y tickets is:

5x + 7(y - x) = 5x + 7y - 7x = 7y - 2x

Answer: A

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