BTGmoderatorDC wrote:In the game Cako, a player is awarded one tick for every third Alb captured, and one click for every fourth Berk captured. The total score is equal to the product of clicks and ticks. If a player has a score of 77, how many Albs did he capture?
(1) The difference between Albs captured and Berks captured is 7.
(2) The number of Albs captured is divisible by 5.
OA A
Source: Manhattan Prep
Given that the product of clicks and ticks = 77 = 7*11, either the number of clicks = 7 and the number of ticks = 11 or vice-versa
Case 1: Say the number of clicks = 7 and the number of ticks = 11
=> # of Albs = 3*7 = 21, 22 or 23. We must stop at 23, else at 24th Alb, one more click will be awarded, making the count of clicks = 8
=> # of Berks = 4*11 = 44, 45, 46, or 47. We must stop at 47, else at 48th Berk, one more tick will be awarded, making the count of ticks = 12
Case 2: Say the number of clicks = 11 and the number of ticks = 7
=> # of Albs = 3*11 = 33, 34 or 35.
=> # of Berks = 4*7 = 28, 29, 30 or 31.
Let's take each statement one by one.
(1) The difference between Albs captured and Berks captured is 7.
To satisfy the above condition, Case 2 is applicable. # of Albs must be 35 and # of Berks must be 28, making their difference = 7.
Sufficient.
(2) The number of Albs captured is divisible by 5.
Insufficient.
The correct answer:
A
Hope this helps!
-Jay
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