A positive integer n has the smallest 3 prime numbers as it

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A positive integer n has the smallest 3 prime numbers as its only prime factors. How many positive integers divide n completely?

(1) The total number of times the prime factors of n occur in n is 5.
(2) The product of the number of times each prime factor of n occurs in n is 4.

Source : e-GMAT
Official Answer : C
Last edited by hazelnut01 on Wed Mar 29, 2017 12:04 am, edited 1 time in total.
Source: — Data Sufficiency |

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by Jay@ManhattanReview » Tue Mar 28, 2017 11:33 pm
ziyuenlau wrote:A positive integer n has the smallest 3 prime numbers as its only prime factors. How many positive integers divide n completely?

(1) The total number of times the prime factors of n occur in n is 5.
(2) The product of the number of times each prime factor of n occurs in n is 4.

Source : e-GMAT
Official Answer : C
Hi ziyuenlau,

The smallest three prime numbers are: 2, 3, and 5

Thus, n = 2^x*3^y*5^z; where x, y, and z are the number of times 2, 3, and 5, respectively, occur in n.

We have to find out how many positive integers divide n completely.

We know that the total number of factors of n = 2^x*3^y*5^z is given by (x+1)(y+1)(z+1)

Thus, the total number of positive integers divide n completely = (x+1)(y+1)(z+1)

If we get the value of x, y and z, we get the UNIQUE answer.

Let's take each statement one by one.

S1: The total number of times the prime factors of n occur in n is 5.

=> x + y + z = 5

We cannot get the unique values of x, y and x.

Case 1: If x = y = 1, and z = 3

The total number of factors of n would be (1+1)(1+1)(3+1) = 2*2*4 =16

Case 2: If x = y = 2, and z = 1

The total number of factors of n would be (2+1)(2+1)(1+1) = 3*3*2 =18

No unique value! Not sufficient!

S2: The product of the number of times each prime factor of n occurs in n is 4.

=> xyz = 4

We cannot get the unique values of x, y and x.

Case 1: If x = y = 1, and z = 4

The total number of factors of n would be (1+1)(1+1)(4+1) = 2*2*5 = 20

Case 2: If x = y = 2, and z = 1

The total number of factors of n would be (2+1)(2+1)(1+1) = 3*3*2 = 18

No unique value! Not sufficient!

S1 and S2:

Only Case 2 works.

Thus, the total number of factors of n would be 18. Sufficient!

The correct answer: C

Hope this helps!

Relevant book: Manhattan Review GMAT Data Sufficiency Guide

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Warsaw | Cape Town | Madrid | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

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by hazelnut01 » Wed Mar 29, 2017 12:03 am
Jay@ManhattanReview wrote:
ziyuenlau wrote:A positive integer n has the smallest 3 prime numbers as its only prime factors. How many positive integers divide n completely?

(1) The total number of times the prime factors of n occur in n is 5.
(2) The product of the number of times each prime factor of n occurs in n is 4.

Source : e-GMAT
Official Answer : C
Hi ziyuenlau,

The smallest three prime numbers are: 2, 3, and 5

Thus, n = 2^x*3^y*5^z; where x, y, and z are the number of times 2, 3, and 5, respectively, occur in n.

We have to find out how many positive integers divide n completely.

We know that the total number of factors of n = 2^x*3^y*5^z is given by (x+1)(y+1)(z+1)

Thus, the total number of positive integers divide n completely = (x+1)(y+1)(z+1)

If we get the value of x, y and z, we get the UNIQUE answer.

Let's take each statement one by one.

S1: The total number of times the prime factors of n occur in n is 5.

=> x + y + z = 5

We cannot get the unique values of x, y and x.

Case 1: If x = y = 1, and z = 3

The total number of factors of n would be (1+1)(1+1)(3+1) = 2*2*4 =16

Case 2: If x = y = 2, and z = 1

The total number of factors of n would be (2+1)(2+1)(1+1) = 3*3*2 =18

No unique value! Not sufficient!

S2: The product of the number of times each prime factor of n occurs in n is 4.

=> xyz = 4

We cannot get the unique values of x, y and x.

Case 1: If x = y = 1, and z = 4

The total number of factors of n would be (1+1)(1+1)(4+1) = 2*2*5 = 20

Case 2: If x = y = 2, and z = 1

The total number of factors of n would be (2+1)(2+1)(1+1) = 3*3*2 = 18

No unique value! Not sufficient!

S1 and S2:

Only Case 2 works.

Thus, the total number of factors of n would be 18. Sufficient!

The correct answer: C

Hope this helps!

Relevant book: Manhattan Review GMAT Data Sufficiency Guide

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Warsaw | Cape Town | Madrid | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.
Why we need to find the total number of factors?