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How about 89 divided by 98?mensanumber wrote:If a two digit integer is divided by an integer formed by reversing its digits, what could be the maximum remainder?
1) 9
2)27
3)36
4)45
5) 54
Sorry, just edited my question.Brent@GMATPrepNow wrote:How about 89 divided by 98?mensanumber wrote:If a two digit integer is divided by an integer formed by reversing its digits, what could be the maximum remainder?
1) 9
2)27
3)36
4)45
5) 54
89 divided by 98 equals 0 with remainder 89
I don't see 89 as an answer choice.
Am I missing something?
Cheers,
Brent
The largest possible remainder is when we divide 94/49 = 1 remainder 45.mensanumber wrote:Consider two integers: an original two digits integer and the integer formed by reversing the digits of this original integer. If the bigger of these two integers is divided by the other integer, what could be the maximum remainder?
1) 9
2)27
3)36
4)45
5) 54
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