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average of temperatures

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by gmatmachoman » Wed Mar 24, 2010 11:22 pm
The average of temperatures at noontime from Monday to Friday is 50; the lowest one is 45, what is the possible maximum range of the temperatures?

1. 20
2. 25
3. 40
4. 45
5. 75
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by neoreaves » Wed Mar 24, 2010 11:29 pm
What we need to know --> Max range

Number of days = 5
Lowest temperature = 45

To increase the Range --> we need to increase the maximum temperature

To do this we need to have 4 days of lowest temperatures = 4(45)
and one day of the highest temperature

Since average of 5 days = 50
Sum = 50(5) = 250
THus max possible temperature = 250 - 4(45) = 70

Max range = 70 - 45 = 25


IMO B
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by harshavardhanc » Thu Mar 25, 2010 12:10 am
gmatmachoman wrote:The average of temperatures at noontime from Monday to Friday is 50; the lowest one is 45, what is the possible maximum range of the temperatures?

1. 20
2. 25
3. 40
4. 45
5. 75
avg of 5 days is 50. View it as 50,50,50,50,50.

Now, min can be 45. Reduce 5 each from rightmost 4 50s and give that 4*5 to the leftmost 50.


70,45,45,45,45.

Range = 70 - 45 = 25.

IMO 2 /B.
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by Scott@TargetTestPrep » Fri Dec 15, 2017 9:47 am
gmatmachoman wrote:The average of temperatures at noontime from Monday to Friday is 50; the lowest one is 45, what is the possible maximum range of the temperatures?

1. 20
2. 25
3. 40
4. 45
5. 75
Since the average of 5 daily temperatures is 50, the sum is 250. To maximize the range, we want one value to be as large as possible. This is done by minimizing the other 4 values. We can minimize the temperatures for 4 of the days, so the sum of the temperatures for those 4 days is 45 x 4 = 180. Thus, the final, maximum temperature, is 250 - 180 = 70 and the maximum range is 70 - 45 = 25.

Answer: B

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