Is 10m > 5n - k?

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m, k and n

by GMATGuruNY » Sun Sep 23, 2018 4:10 am

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BTGmoderatorDC wrote:Is 10m > 5n - k?

(1) n = 2m
(2) |k| = -k
Statement 1: n=2m
Substituting n=2m into 10m > 5n-k, we get:
10m > 5(2m) - k ?
10m > 10m - k ?
0 > -k ?
k > 0 ?
No way to determine whether k>0.
INSUFFICIENT.

Statement 2: |k| = -k
This equation is valid only if k≤0.
No information about m or n.
INSUFFICIENT.

Statements combined:
Statement 1: Is k > 0?
Statement 2: k ≤ 0
Thus, the answer to the rephrased question stem yielded by Statement 1 is NO.
SUFFICIENT.

The correct answer is C.
Last edited by GMATGuruNY on Sun Sep 23, 2018 7:21 am, edited 1 time in total.
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by fskilnik@GMATH » Sun Sep 23, 2018 7:13 am

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BTGmoderatorDC wrote:Is 10m > 5n - k?

(1) n = 2m
(2) |k| = -k

Source: Veritas Prep
$$10m\,\,\mathop > \limits^? \,\,5n - k$$

$$\left( 1 \right)\,\,\,n = 2m\,\,\,\,\left\{ \matrix{
\,{\rm{Take}}\,\,\,\left( {n,m,k} \right) = \left( {0,0,0} \right)\,\,\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\rm{NO}}} \right\rangle \,\,\,\, \hfill \cr
\,{\rm{Take}}\,\,\,\left( {n,m,k} \right) = \left( {2,1,1} \right)\,\,\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\rm{YES}}} \right\rangle \,\,\,\, \hfill \cr} \right.\,$$

$$\left( 2 \right)\,\,\,\,\left| k \right| = - k\,\,\,\, \Leftrightarrow \,\,\,\,k \le 0$$
$$\left\{ \matrix{
\,{\rm{Take}}\,\,\,\left( {n,m,k} \right) = \left( {0,0,0} \right)\,\,\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\rm{NO}}} \right\rangle \,\,\,\, \hfill \cr
\,{\rm{Take}}\,\,\,\left( {n,m,k} \right) = \left( {0,1, - 1} \right)\,\,\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\rm{YES}}} \right\rangle \,\,\,\, \hfill \cr} \right.$$

$$\left( {1 + 2} \right)\,\,\,\left\{ \matrix{
10m\,\,\mathop > \limits^? \,\,5\left( {2m} \right) - k\,\,\,\,\, \Leftrightarrow \,\,\,\,k\,\,\mathop > \limits^? \,\,0 \hfill \cr
k \le 0 \hfill \cr} \right.\,\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,\left\langle {{\rm{NO}}} \right\rangle \,\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,{\rm{SUFF}}.$$


This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
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