BTGmoderatorDC wrote: ↑Mon Aug 24, 2020 6:09 pm
mgmat.PNG
Given the figure, what is y2?
(1) y1 is 1.5
(2) x1 is -2
OA
C
Source: Manhattan Prep
Firstly, recall the equation of the line in the form \(y=mx+b\)
Statement 1: Implies \(1.5=0+c\) (at \(x=0\))
So the equation of the line is \(y=mx+1.5\), but we cannot calculate \(m\) from this information. Insufficient \(\Large{\color{red}\chi}\)
Statement 2: \(0=−2m+b\) (substituting the value of \(x_1 \& y_1\)). From this we cannot calculate \(m \& b\). Insufficient \(\Large{\color{red}\chi}\)
Combining \(1 \& 2\), we get
\(2m=1.5 \Longrightarrow m=\dfrac{1.5}{2}\)
Hence, the equation of the line \(y=\dfrac{1.5}{2}x+1.5 \Longrightarrow 2y=1.5x+3\)
Therefore, the value of \(y_2\) can be calculated by substituting the value of \(x_2=5\) in the above equation. Sufficient \(\Large{\color{green}\checkmark}\)
Hence,
C
