Arithmetic

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swerve: Legendary Member; Posts: 2499; Joined: Sun Oct 29, 2017 2:04 pm; Followed by:6 members

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If the sum of three consecutive integers is k, then which of the following is a possible value of k?

A. 199
B. 200
C. 201
D. 202
E. 203

The OA is C

Source: Magoosh

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Source: Beat The GMAT — Problem Solving | Thu Oct 01, 2020 10:01 am

psarma: Junior | Next Rank: 30 Posts; Posts: 24; Joined: Wed Jun 29, 2011 1:47 am

Re: Arithmetic

by psarma » Thu Oct 01, 2020 3:33 pm

Let the 3 consecutive integers be n, n+1 and n+2
Given, n+(n+1)+(n+2)=k
or 3n+3=k
or 3(n+1)=k
i.e k is thus a multiple of 3.

From the options given, only 201 is a multiple of 3.

Answer C.

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Scott@TargetTestPrep: GMAT Instructor; Posts: 8088; Joined: Sat Apr 25, 2015 10:56 am; Location: Los Angeles, CA; Thanked: 43 times; Followed by:29 members

Re: Arithmetic

by Scott@TargetTestPrep » Tue Oct 06, 2020 3:17 am

swerve wrote: ↑
Thu Oct 01, 2020 10:01 am
If the sum of three consecutive integers is k, then which of the following is a possible value of k?

A. 199
B. 200
C. 201
D. 202
E. 203

The OA is C

Solution:

Since the sum of any three consecutive integers must be a multiple of 3 (e.g., 1 + 2 + 3 = 6; 8 + 9 + 10 = 27, etc.), then k could be 201 (notice that it’s the only number in the given choices that is a multiple of 3).

Answer: C

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