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\(x\) is between

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Re: \(x\) is between

by psarma » Thu Oct 01, 2020 3:21 pm
Right angled triangle,
so \(x^2\) + 10 = \(\left(2\sqrt{\left(15\right)}\right)^2\)
Solving for x:
\(x^2\) =50
or x= \(\sqrt{50}\)
Thus, answer is Option D - between 7 & 8
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Re: \(x\) is between

by Scott@TargetTestPrep » Tue Oct 06, 2020 3:19 am
Gmat_mission wrote: ↑
Thu Oct 01, 2020 7:06 am
 GMAT_PS_Magoosh_200.png

\(x\) is between

A. 4 and 5
B. 5 and 6
C. 6 and 7
D. 7 and 8
E. 8 and 9

Answer: D

Solution:

Using the Pythagorean theorem, we have:

x^2 + (√10)^2 = (2√15)^2

x^2 + 10 = 60

x^2 = 50

x = √50

Since 49 < 50 < 64, √49 < √50 < √64. That is, 7 < x < 8.

Answer: D

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