gmatter2012 wrote:Last Sunday a certain store sold copies of Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each, and the store sold no other newspapers that day. If r percent of the store's revenues from newspaper sales was from Newspaper A and if p percent of the newspapers that the store sold were copies of newspaper A, which of the following expresses r in terms of p?
A. 100p / (125 - p)
B. 150p / (250 - p)
C. 300p / (375 - p)
D. 400p / (500 - p)
E. 500p / (625 - p)
Answer Reveal : D
This one really got me frustrated, I seek relief here !![spoiler][/spoiler]
Plug in values that make the math easy.
Let the number of copies of B sold = 4, so that the revenue from B = 4(1.25) = 5.
Let the number of copies of A sold = 4, so that the revenue from A = 4*1 = 4.
Since (copies of A)/(total copies) = 4/8 = 1/2, p = (1/2)100 = 50.
Since (revenue from A)/(total revenue) = 4/9, r = (4/9)100 = 400/9. This is our target.
Now we plug p=50 into the answers to see which yields our target of 400/9.
Answer choice
D looks like a good bet, since it includes 400:
(400*50)/(500-50) = (400*50)/450 = 400/9.
The correct answer is
D.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at
[email protected].
Student Review #1
Student Review #2
Student Review #3
