If each line segment in the figure is equal to 4, we're looking for the area of 3 equal RHOMBUSES (rhombi? No one knows).
(Forgive the crude rendering... geometry is always the hardest to explain digitally!)
If the angles a, b, and c are all 60, then the opposite angles are 60, and the other angles 120:
This means that we can chop each rhombus into 2 identical EQUILATERAL triangles. (Btw, the 60-120-60-120 rhombus is the most common form of a rhombus on the GMAT).
Now, we can simply calculate the area of a single equilateral triangle, then multiply by 6.
AREA OF EQUILATERAL: remember that you can chop an equilateral triangle into two 30-60-90 right triangles. You should have the ratio for these memorized:
Thus, the base of each triangle is 4, and the height is 2(sqrt3). So (1/2)bh = 4(sqrt3)
Since we have 6 such equilateral triangles, the total area = (6)(4(sqrt3)) = 24(sqrt3)
The answer is
E.
