Mo2men wrote:Dear Experts,
I wonder how Mitch reaches that j=4 & k=3 and does not satisfies individual equations, while in Brent's first solution proves that J & K are not integer individually because 3 = 2^(4/k) & 2^(j/3) = 3.
Can any expert elaborate more as question seems strange?
thanks
In my solution above, I had in mind the following number property rule:
If (a^r)(b^s)(c^t) = (a^x)(b^y)(c^z), then rst = xyz.
I've revised my post to clarify the reasoning.
A logarithmic proof for this number property rule:
(a^r)(b^s)(c^t) = (a^x)(b^y)(c^z)
log(a^r) * log(b^s) * log(c^t) = log(a^x) * log(b^y) * log(c^z)
r(log a) * s(log b) * t(log c) = x(log a) * y(log b) * z(log c)
rst = xyz.
Please note that this proof is beyond the scope of the GMAT.
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