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Four concentric circles share the same center. The smallest circle has a radius of \(1\) inch. For \(n\) greater than \(1,\) the area of the \(nth\) smallest circle in square inches, \(A_n,\) is given by \(A_n=A_{n-1}+(2n-1)\pi.\)
What is the sum of the areas of the four circles, divided by the sum of their circumferences, in inches?
A. \(1\)
B. \(1\frac12\)
C. \(2\)
D. \(2\frac12\)
E. \(3\)
Answer: B
Source: Manhattan GMAT
What is the sum of the areas of the four circles, divided by the sum of their circumferences, in inches?
A. \(1\)
B. \(1\frac12\)
C. \(2\)
D. \(2\frac12\)
E. \(3\)
Answer: B
Source: Manhattan GMAT
