Timer
00:00
Your Answer
A
B
C
D
E
Global Stats
Manhattan Prep
$$\text{For all positive integers n, the sequence } A_n \text{ is defined by the following relationship:}$$
$$A_n=\frac{n-1}{n!}$$
$$\text{What is the sum of all the terms in the sequence from } A_1 \text{ through } A_{10}, \text{ inclusive?}$$
$$\text{A. }\frac{9!+1}{10!}$$
$$\text{B. }\frac{9(9!)}{10!}$$
$$\text{C. }\frac{10!-1}{10!}$$
$$\text{D. }\frac{10!}{10!+1}$$
$$\text{E. }\frac{10(10!)}{11!}$$
OA C
$$\text{For all positive integers n, the sequence } A_n \text{ is defined by the following relationship:}$$
$$A_n=\frac{n-1}{n!}$$
$$\text{What is the sum of all the terms in the sequence from } A_1 \text{ through } A_{10}, \text{ inclusive?}$$
$$\text{A. }\frac{9!+1}{10!}$$
$$\text{B. }\frac{9(9!)}{10!}$$
$$\text{C. }\frac{10!-1}{10!}$$
$$\text{D. }\frac{10!}{10!+1}$$
$$\text{E. }\frac{10(10!)}{11!}$$
OA C
