Last month 15 homes were sold in Town X

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Last month 15 homes were sold in Town X

by jain2016 » Sun May 08, 2016 4:48 am
Last month 15 homes were sold in Town X. The average(arithmetic mean) sale price of the homes was $150,000 and the median sale price was $130,000. Which of the following statements must be true?

1) At least one of the homes was sold for more than $165,000
2) At least one of the homes was sold for more than $130,000 and less than $150,000.
3) At least one of the homes was sold for less than $130,000

A) 1 only
B) 2 only
C) 3 only
D) 1 and 2
E) 1 and 3

OAA

Hi Experts ,

Please explain.

Many thanks in advance.

SJ
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by Brent@GMATPrepNow » Sun May 08, 2016 5:53 am
Last month, 15 homes were sold in Town X. The average sale price of the homes was $150,000 and the median sale price was $130,000. Which of the following statements must be true?

I. at least one of the homes was sold for more than $165,000
II. at least one of the homes was sold for more than $130,000 but less than $150,000
III. at least one of the homes was sold for less than $130,000

A) I only
B) II only
C) III only
D) I and II only
E) I and III only

OA A
The key word in this question is MUST. As in, which of the following MUST be true?. So, if it's possible that one scenario is not true, we can eliminate it.

So, let's looks at one possible scenario and see which answer choices we can eliminate.

Aside: To make things simpler, let's divide all of the prices by 1000.

First, we'll use a nice rule that says: sum of all values = (mean)(number of values)
So, the sum of all 15 prices = ($150)(15) = $2250.

If the median is $130, then the middlemost value is $130

So, one possible scenario is:
130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 430

Aside: To find the last value (430), I took the sum of all 15 numbers (2250) and subtracted (14)(130)

Notice that this scenario tells us that II and III need not be true (since our scenario does not conform to either one).

Since answer choices B, C, D and E all include either II or III, we can eliminate them.

This leaves us with A, which must be the correct answer.

Cheers,
Brent
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by Matt@VeritasPrep » Thu May 12, 2016 12:10 am
Just as an aside, this is a great question for which to search the forum. These older GMATPrep Q's have been discussed at great length in the past, with many fine explanations. (Brent's is great too!)

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by Scott@TargetTestPrep » Wed Jan 03, 2018 4:26 pm
jain2016 wrote:Last month 15 homes were sold in Town X. The average(arithmetic mean) sale price of the homes was $150,000 and the median sale price was $130,000. Which of the following statements must be true?

1) At least one of the homes was sold for more than $165,000
2) At least one of the homes was sold for more than $130,000 and less than $150,000.
3) At least one of the homes was sold for less than $130,000

A. I only
B. II only
C. III only
D. I and II
E. I and III
We are given that last month 15 homes were sold in Town X. The average (arithmetic mean) sale price of the homes was $150,000 and the median sale price was $130,000. We can start by reducing $150,000 and $130,000 by dividing each number by 1,000.

We now have that the mean sale price of the homes was $150 and that the median sale price was $130. Let's now analyze the statements to determine which MUST be true.

I. At least one of the homes was sold for more than $165,000.

(We can rephrase Roman numeral I as: At least one of the homes was sold for more than $165.)

To determine whether the above statement MUST be true, let's see if we can find a scenario in which none of the homes is priced for more than $165. Furthermore, since the median price is $130, let's create a scenario in which the 8th value of the 15 values (i.e., the middle number) is 130, the first 7 values are all 130, and the last 7 values are all 165:

130, 130, 130, 130, 130, 130, 130, 130, 165, 165, 165, 165, 165, 165, 165, 165

If this is the case, the sum would be 130 x 8 + 165 x 7 = 1,040 + 1,155 = 2,195. However, since the average home price is $150, the sum of the home prices is 150 x 15 = 2,250. This means at least one of the numbers in the list above has to be changed to a number greater than 165 to make up the difference between 2,195 and 2,250. (For example, since the difference is 55, we can change the last number 165 to 220 to make up this difference.)

So, Roman numeral I is correct.

II. At least one of the homes was sold for more than $130,000 and less than $150,000.

(We can rephrase II as: At least one of the homes was sold for more than $130 and less than $150)

When analyzing Roman numeral I, we showed that none of the homes had to be priced between $130 and $165. Roman numeral II is not correct.

III. At least one of the homes was sold for less than $130,000.

(We can rephrase III as: At least one of the homes was sold for less than $130.)

When analyzing Roman numeral I, we showed that none of the homes had to be priced at less than $130. Roman numeral III is not correct.

Answer: A

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by Brent@GMATPrepNow » Wed Jan 03, 2018 4:30 pm
Last month, 15 homes were sold in Town X. The average sale price of the homes was $150,000 and the median sale price was $130,000. Which of the following statements must be true?

I. at least one of the homes was sold for more than $165,000
II. at least one of the homes was sold for more than $13,000 but less than $150,000
III. at least one of the homes was sold for less than $130,000

A) I only
B) II only
C) III only
D) I and II only
E) I and III only

OA A
The key word in this question is MUST. As in, which of the following MUST be true. So, if it's possible that one scenario is not true, we can eliminate it.

So, let's looks at one possible scenario and see which answer choices we can eliminate.

Aside: To make things simpler, let's divide all of the prices by 1000.

First, we'll use a nice rule that says: sum of all values = (mean)(number of values)
So, the sum of all 15 prices = ($150)(15) = $2250.

If the median is $130, then the middlemost value is $130

So, one possible scenario is:
130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 430

Aside: To find the last value (430), I took the sum of all 15 numbers (2250) and subtracted (14)(130)

Notice that this scenario tells us that II and III need not be true (since our scenario does not conform to either one).

Since answer choices B, C, D and E all include either II or III, we can eliminate them.

This leaves us with A, which must be the correct answer.

Cheers,
Brent
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